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x^2+(x-1)^2=(2x-1)(x+3)
We move all terms to the left:
x^2+(x-1)^2-((2x-1)(x+3))=0
We multiply parentheses ..
x^2-((+2x^2+6x-1x-3))+(x-1)^2=0
We calculate terms in parentheses: -((+2x^2+6x-1x-3)), so:We get rid of parentheses
(+2x^2+6x-1x-3)
We get rid of parentheses
2x^2+6x-1x-3
We add all the numbers together, and all the variables
2x^2+5x-3
Back to the equation:
-(2x^2+5x-3)
x^2-2x^2-5x+(x-1)^2+3=0
We add all the numbers together, and all the variables
-1x^2-5x+(x-1)^2+3=0
We move all terms containing x to the left, all other terms to the right
-1x^2-5x+(x-1)^2=-3
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